
Ashley
You push your physics book 2.30 m along a horizontal tabletop with a horizontal push of 3.00 N while the opposing force of friction is 0.650 N.
A)How much work does your 3.00 N push do on the book?
B)How much work does the friction force do on the book?
C)How much work does the normal force from the table do on the book?
Answer
A) Work done= Total Force*s(s is distance travelled). 3*2.30= 9.9
B) The friction has travelled 2.3 as well I'm guessing so 2.3*0.650=1.495
C) I'd think you'd need the weight of the book? mg=R times the distance I think
A) Work done= Total Force*s(s is distance travelled). 3*2.30= 9.9
B) The friction has travelled 2.3 as well I'm guessing so 2.3*0.650=1.495
C) I'd think you'd need the weight of the book? mg=R times the distance I think
How many pages does each book have?

D1ckhead S
Book A exceeds Book C by 18,000 pages.
Book A and Book C combined, has 20,000 pages.
Determine how many pages each book has?
(Need steps), thanks.
Answer
The mathematical statement of the first fact is
A = C + 18000
and the second statement is
A + C = 20000.
Substituting the first equation into the second gives
C + 18000 + C = 20000 ==> 2C = 2000 ==> C = 1000.
Using the first equation gives A = 1000 + 18000 = 19000.
The mathematical statement of the first fact is
A = C + 18000
and the second statement is
A + C = 20000.
Substituting the first equation into the second gives
C + 18000 + C = 20000 ==> 2C = 2000 ==> C = 1000.
Using the first equation gives A = 1000 + 18000 = 19000.
Powered by Yahoo! Answers
Comments :
Post a Comment